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How many aluminum ions are in 12 grams of aluminum oxide? - Printable Version +- Forums (https://askaluminium.com) +-- Forum: My Category (https://askaluminium.com/forumdisplay.php?fid=1) +--- Forum: aluminium faq (https://askaluminium.com/forumdisplay.php?fid=2) +--- Thread: How many aluminum ions are in 12 grams of aluminum oxide? (/showthread.php?tid=8188) |
How many aluminum ions are in 12 grams of aluminum oxide? - 1-LVDCPN - 09-18-2018 Aluminium oxide has the formula Al22O33. This has a formula mass of 101.96 g mol−1−1. That means that 12 g of Al22O33 contain 12 g / 101.96 g mol−1−1 = 0.118 moles of Al22O33. Each Al22O33 formula unit contains two Al3+3+ ions, so there are 2 x 0.118 mol = 0.235 moles of Al3+3+ ions. If you want an actual number, you can multiply that by Avogadro’s constant: 0.235 mol x 6.022 x 102323 mol−1−1 = 1.42 x 102323 ions. |